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3x^2-640x+30000=0
a = 3; b = -640; c = +30000;
Δ = b2-4ac
Δ = -6402-4·3·30000
Δ = 49600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{49600}=\sqrt{1600*31}=\sqrt{1600}*\sqrt{31}=40\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-640)-40\sqrt{31}}{2*3}=\frac{640-40\sqrt{31}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-640)+40\sqrt{31}}{2*3}=\frac{640+40\sqrt{31}}{6} $
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